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Statistical Methods Assignment - Research Paper Example

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In a t distribution, as the degree of freedom reaches infinity, the size of the 1% and 5% values of the t are the same as that for z. That is, it reaches 1.96 for 95% critical values and 1.64 for 90% critical values.
The two intervals do not seem to have a significant difference between them…
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Statistical Methods Assignment
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Since this is a weight reduction study, we did a one-directional t test. Results showed that the diet resulted in a significant decrease in weight, both for a 90% and 95% confidence level. In both cases, it is reasonable to say that two-thirds of the general population agrees with the principle of University top-up fees. The hypothesized p is included in both intervals. We, therefore, do not reject the null hypothesis. . : 0.05 p = 2*0.0096 = 1 - 0.9808 = 0.0192The test shows that there is a significant statistical difference between the sample mean and the hypothesized mean, on a 95% confidence level.

We, therefore, reject the null hypothesis.Question 6sample size 121 degree of freedom 120sample mean 47.50 critical t 1.658sample standard deviation 7.5090% confidence interval (46.37, 48.63)Assuming that the population standard deviation is equal to the sample standard deviation, the confidence interval becomes: (46.38, 48.62)The two intervals do not seem to have a significant difference between them. This is a result of having a large sample size. As the sample size increases, the difference between the two intervals is also expected to significantly increase, resulting to large errors.

Question 7 t ratio3.364alpha ()critical t0.052.306reject H00.101.860reject H0In this test, we assume that the sample standard deviation approximates that of the population without any significant statistical difference. Since this is a weight reduction study, we did a one-directional t test. Results showed that the diet resulted in a significant decrease in weight, both for a 90% and 95% confidence level.Question 8T680N1050T/n0.648p0.667standard deviation0.228 Test Statistic 1.29 (1.29) 0.

9015 p value 0.1970 95% confidence interval (0.619, 0.677) 90% confidence interval (0.623, 0.672)In both cases, it is reasonable to say that two-thirds of the general population agrees with the principle of University top-up fees. The hypothesized p is included in both intervals. We, therefore, do not reject the null hypothesis.Question 9To estimate a population proportion p with a 95% confidence

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